Question

find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function

f(x)=x^2-4x-5

Answer 1

F(x) = Y = X^2 - 4X - 5, h = Xv = -b/2a
= 4/2 = 2, K = Yv = 2^2 - 4(2) -5 = -9
V(h,K), V(2,-9). Since a is positive,
the graph opens upward and the vertex
is the min. point on thr graph. To graph the function,select values of X to the left and right of the vertex and
calculate the corresponding value of Y: (0,-5) (1,-8), V(2,-9), (3,-8),
(4,-5).
Line of symmetry:X = 2

a = coefficient of X^2.
h = X-coordinate of vertex.
K = Y- coordinate of vertex.