Question

find the vertex, the line of symmetry and the maximum or minimum value of f(x). graph the function. f(x)=-(x+6)^2-2

The vertex is The line of symmetry is x=
The minimum/maximum value of f(x) is?
The value of f(-6) =-2 is maximum or minimum?
and the graph goes up or down.
Thank you

Answer 1

and your thinking is? I will be happy to critique your thinking. It will do you little lasting good if I do these for you.

Answer 2

I believe that x=-2 and the maximum is -2 and the graph goes downward. I did do some excerises with my school work but haven't mastered this.
pls let me know if I have anything right. I appericate you pushing me to find the answer.

Answer 3

"I believe that x=-2 and the maximum is -2 and the graph goes downward...."
How did you find the maximum of f(x)?

Try a tabulation of f(x) from -10 to 0 and see if you spot the maximum at -2 or elsewhere.

You will find that the function was expressed in the form for a reason:
f(x) = A(x-k)² + B

Answer 4

ok the vertex is (-6,2) the line of symmetry is x=-6 and the vlue is max at 2, the graph goes downward. can someone please tell me if I am right. I am trying here.

Answer 5

Could you please verify from your tabulation the value of f(x) when x = -6 (i.e. at the vertex)?
Otherwise the rest are correct.