Asked by patti

find the vertex and line of symmetry
f(x)=x^2-6x+8
f(x)=3x^2-18x+6
f(x)=4x^2-8x+
f(x)=-2(x+6)^2+6

15 years ago

Answered by Anonymous

f(x)=x^2-6x+8=2x-6

15 years ago

Answered by ali

f(x)=3x^2-18x+6=6x-18

15 years ago

Answered by ali

f(x)=4x^2-8x+=8x-8

15 years ago

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