Question

find the vertex and line of symmetry
f(x)=x^2-6x+8
f(x)=3x^2-18x+6
f(x)=4x^2-8x+
f(x)=-2(x+6)^2+6

Answer 1

f(x)=x^2-6x+8=2x-6

Answer 2

f(x)=3x^2-18x+6=6x-18

Answer 3

f(x)=4x^2-8x+=8x-8