Asked by Jess

find the vertex, line of symmetry, and minimum or maxium values of the quadratic equation
f(x)=9-x^2
Answered by Henry
F(x) = Y = -X^2 + 9.

h = Xv = -b/2a = 0/-2 = 0.

k = Yv = 0^2 + 9 = 9.

V(h,k) = (0,9).

The max. value is at the vertex and is equal to 9.
Answered by Henry
The line of symmetry = h = 0.
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