find the vertex, axis of symmetry,y int and third point
3x^2-12x+10
Can someone give me a youtube link for this
2 answers
-15x+12
The question probably was
y = 3x^2-12x+10
I will assume you are not taking Calculus, and will do it by completing the square.
y = 3(x^2-4x + 4 - 4) + 10
= 3((x-2)^2 - 4) + 10
= 3(x-2)^2 - 12 + 10
= 3(x-2)^2 - 2
vertex: (2,-2)
axis of symmetry : x = 2
y-intercept : 10
y = 3x^2-12x+10
I will assume you are not taking Calculus, and will do it by completing the square.
y = 3(x^2-4x + 4 - 4) + 10
= 3((x-2)^2 - 4) + 10
= 3(x-2)^2 - 12 + 10
= 3(x-2)^2 - 2
vertex: (2,-2)
axis of symmetry : x = 2
y-intercept : 10