Asked by jacqueline
Help me find the axis of symmetry of the given funtion.
Y=x2-2x+4
Y=x2-2x+4
Answers
Answered by
bobpursley
That equation has no real roots.
b^2-4ac=4-16=-12
so the square root of that is not real.
b^2-4ac=4-16=-12
so the square root of that is not real.
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