Question

f(x)=-x^2 - 3x
Find the axis of symmetry, vertex, direction it opens, and write the equation in vertex form.

If f(x) =x^2 + 2x
g(x)= x-9
h(x) = 3x - 2
Find [f o g o h] (-2)


Please explain how you got it I'm really confused right now.

Answer 1

You have to know how to complete the square.

f(x) = -x^2 - 3x
= -(x^2 + 3x <b>+9/4 - 9/4</b>)
= -( (x + 3/2)^2 - 9/4)
= -(x + 3/2)^2 + 9/4

take it from there, all the information is just there in front of you

for you 2nd problem, [f o g o h] (-2) means
f(g(h(-2))) to me
= f(g(-8))
= f(-17)
= (-17)^2 + 2(-17)
= 255