Question
I need to find the vertex, axis of symmetry, and if the graph will open upward or downword
f(x)=-3x^2-5
f(x)=-3x^2-5
Answers
Steve
There's gotta be a review section in your text that says:
y - (-5) = -3(x-0)^2
so vertex = (0,-5)
axis of symmetry = -b/2a = 0/-6 = 0
since the coefficient of x^2 < 0, it opens downward.
y - (-5) = -3(x-0)^2
so vertex = (0,-5)
axis of symmetry = -b/2a = 0/-6 = 0
since the coefficient of x^2 < 0, it opens downward.