Find the vertex and the axis of symmetry for the parabola with the given equation y=5x2-30+47....

Answer 1

I will assume you have a typo, with the first term 5x^2 and that the second term is -30x

the x of the vertex = -b/(2a) = 30/(10) = 3
sub in x=3
y = 5(9) - 30(3) + 47 = 2

vertex (3,2)
axis of symmetry : x = 3

Answer 2

Thanks, I was getting something like 9
now I see what I did wrong.