Question

An electron moves at a speed of 5.4 106 m/s perpendicular to a constant magnetic field. The path is a circle of radius 1.0 10-3 m.

(a) What is the magnitude of the field?
T

(b) Find the magnitude of the electron's acceleration.
m/s2

Answer 1

force= Me*v^2/r= qBv
solve for r