Asked by Mary
An electron moves at a speed of 5.4 106 m/s perpendicular to a constant magnetic field. The path is a circle of radius 1.0 10-3 m.
(a) What is the magnitude of the field?
T
(b) Find the magnitude of the electron's acceleration.
m/s2
(a) What is the magnitude of the field?
T
(b) Find the magnitude of the electron's acceleration.
m/s2
Answers
Answered by
bobpursley
force= Me*v^2/r= qBv
solve for r
solve for r
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