Question

An electron moves at 5 * 10^6 m/s. Predict the position of the electron within a 1% uncertainty (margin of error). Calculate the uncertainty, which is the worst possible speed (v), of the electron. Remember, based on Heisenberg's Uncertainty Principle, this should also indirectly tell the uncertainty of its position (delta x).

Answer 1

∆v * ∆p > h
so plug in the numbers and solve for ∆p

Answer 2

actually, I forgot that p is usually used for momentum. So, using x for position,
∆p * ∆x > h
and p includes the mass of the electron.