Asked by sweety


When an electron moves from A to B along an electric field line in Fig. 24-29, the electric field does 3.66 x 10-19 J of work on it. What are the electric potential differences (a)VB - VA, (b)VC - VA, and (c)VC - VB?
in the picture there r four field lines going from down to up that is from B to A. C is on otheer field line along the curve joining B with C. they r in eqvipotential
Answered by drwls
The potential energy difference EB - EA equals the charge (-e) times the voltage difference. Thus
3.66*10^-19 J = (-1.60*10^-19 C)(VB - VA)
VB - VA = 2.3 Volts

B and C are along what is called an equipotential line, not a field line.
Field lines are everywhere perpendicular to equipotential lines.
Therefore VC - VA = 0

Since VC = CA, VC - VB = VA - VB
= -2.3 V
Answered by John
drwls, that didn't work for my problem.
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