Asked by Veronika
An electron moves at a speed of 6.0 x 10^-6 perpendicular to a constant magnetic field. The path is a circle of radius 1.3 x 10^-3m.
What is the magnitude of the field.
Find the magnitude of the electron acceleration.
What is the magnitude of the field.
Find the magnitude of the electron acceleration.
Answers
Answered by
drwls
centripetal force = magnetic force
m V^2/R = e V B, so
B = (m/e)*(V/R)
m and e are the electron mass and charge
electron acceleration = V^2/R
m V^2/R = e V B, so
B = (m/e)*(V/R)
m and e are the electron mass and charge
electron acceleration = V^2/R
Answered by
drwls
You forgot to include the units for speed. 6*10^-6 is very slow if you are talking about m/s. Are you sure you gor the exponent right?
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