Asked by Anonymous
An electron moves to the left with a velocity of 3.2 x 10^5 m/s and has a magnetic force of 5.6 x 10^-17 N exerted on it. What is the magnitude of the magnitude field? Assume the charge has a value of 1.60 x 10^-19 C.
Answers
Answered by
bobpursley
Fm=Bqv
solve for B
solve for B
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.