Asked by jh

cot(theta)= 3
pi < theta < 3pi/2
Find:
sin(theta)= -1 ?
cos(theta)= -3 ?
tan(theta)= 1/3 ?
sec(theta)= -1/3 ?
csc(theta)= -1 ?

That's what I came up with, but they are not correct, PLEASE help me where I went wrong!!
Answered by bobpursley
tan theta= 1/3 which means sintheta 1/sqr10
draw the triangle Notice it is in the third quadrant, where cosine is negative.
Answered by Damon
You do not seem to have calculated the hypotenuse which you need for sin and cos and sec and csc
sqrt (1^2+3^2) = sqrt 10
Answered by jh
So,
tan(theta)=sin(theta)/cos(theta)
cos(theta)=sin(theta)/tan(theta)
=(1/sqrt(10))/(1/3)
= 3/sqrt(10) ??
But its incorrect!! What am I doing wrong?
Answered by Josie
If sin t=-1/4, find sin t + 6pi
Answered by Kayla
tan theta= 5 divided by 12 and theta is in quadrant 3 what does sin 2 theta equal
There are no AI answers yet. The ability to request AI answers is coming soon!