Asked by Tara
tan^2BeatacscBeta-tan^2 (simplify)
(sin/cos)^2Beta times 1/sin-(sin/cos)^2
(sin^2/cos^2)-(sin^2/cos^2)=-sin/cos
Is this correct?
(sin/cos)^2Beta times 1/sin-(sin/cos)^2
(sin^2/cos^2)-(sin^2/cos^2)=-sin/cos
Is this correct?
Answers
Answered by
Damon
(s^2/c^2)(1/s) - s^2/c^2
(s^2/c^2) [ 1/s -1 ]
(s^2/c^2)(1-s)/s
(s/c^2)(1-s)
I do not know what more can be done.
(s^2/c^2) [ 1/s -1 ]
(s^2/c^2)(1-s)/s
(s/c^2)(1-s)
I do not know what more can be done.
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