Asked by kim
can some one tell me the simplified cube radical form of (64x^3y^7)^1/3
Answers
Answered by
Reiny
(64x^3y^7)^1/3
= 4 x y^(7/3)
now look at the y^(7/3) part
y^(7/3) = y^(6/3) (y^(1/3))
= y^2 y^(1/3)
so final answer
= 4xy^2 y^(1/3)
= 4 x y^(7/3)
now look at the y^(7/3) part
y^(7/3) = y^(6/3) (y^(1/3))
= y^2 y^(1/3)
so final answer
= 4xy^2 y^(1/3)
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