Question

A gun fires a shell at an angle of elevation of 30 degree with a velocity of 2×10m what are the horizontally and vertical components of the velocity? What is the range of the shell?how high will it rise

Answer 1

Please i want the ans

Answer 2

initial velocity up = Vi = whatever you typed * sin 30
sin 30 = 1/2
horizontal velocity forever = u = same whatever * cos 30 = 0.866 * whatever
for height
(1/2) m Vi^2 = m g h
h = Vi^2 / 2g
how long in the air?
v = Vi - g t
v = 0 at top
so t = Vi/g at top
has to fall then so time in air = 2 Vi/g
then range = u * 2 Vi/g