Asked by Joy
A particle starts from rest and moves with a constant acceleration of 0.5m/s2. Calculate the time taken by the particle to cover a distance of 25m.
Answers
Answered by
bobpursley
vf^2=vi^2+2ad
vf^2=2*.5*25=25
vf=5m/s
time= distance/avgvelocity=25/(5/2)=10 seconds
vf^2=2*.5*25=25
vf=5m/s
time= distance/avgvelocity=25/(5/2)=10 seconds
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