Question
A particle, which starts from rest, covers a distance of 19.94 cm in the first 8.6 seconds. Find the acceleration (in m/s2) of the particle at the end of 8.6 seconds.
Answers
MathMate
If we assume uniform acceleration, we can use:
ΔX=(v0)t+(1/2)at^2
v0=initial velocity = 0 m/s
t=time=8.6 s
ΔX=displacement=0.1994 m
Solve for a (in m/s^2)
ΔX=(v0)t+(1/2)at^2
v0=initial velocity = 0 m/s
t=time=8.6 s
ΔX=displacement=0.1994 m
Solve for a (in m/s^2)