Asked by thiru

a particle at rest starts in horizontal strsight line with uniform acceleration ratio distance during 4th and 3rd sec



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Answers

Answered by bobpursley
distance=1/2 a t^2

distance during third second:
1/2 a (3^2-2^2)
distance during fourth second:
1/2 a (4^2-3^2)

ratio distance during 4th to 3rd:

(16-9)/(9-4)=7/5
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