Question
a particle at rest starts in horizontal strsight line with uniform acceleration ratio distance during 4th and 3rd sec
ond
ond
Answers
bobpursley
distance=1/2 a t^2
distance during third second:
1/2 a (3^2-2^2)
distance during fourth second:
1/2 a (4^2-3^2)
ratio distance during 4th to 3rd:
(16-9)/(9-4)=7/5
distance during third second:
1/2 a (3^2-2^2)
distance during fourth second:
1/2 a (4^2-3^2)
ratio distance during 4th to 3rd:
(16-9)/(9-4)=7/5