Asked by Physics
At t= 0, a particle starts from rest at x= 0, y= 0, and moves in the xy plane with an acceleration ->a (vector) = (4.0ihat+ 3.0jhat)m/s^2. Assume t is in seconds.
Determine the x component of velocity as a function of time t.
Determine the y component of velocity as a function of time t.
Determine the speed of the particle as a function of time t.
Determine the position of the particle as a function of time t.
Determine the x component of velocity as a function of time t.
Determine the y component of velocity as a function of time t.
Determine the speed of the particle as a function of time t.
Determine the position of the particle as a function of time t.
Answers
Answered by
drwls
4.0 is the acceleration in the x direction (with the i-hat unit vector)) and 3.0 is the acceleration in the y direction (with the j-hat unit vector).
Vx = 4.0 t Vy = 3.0 t
V = sqrt(V2^2 + Vy^2) = 5 t
Integrate Vx and Vy for the x and y locations vs. t.
Vx = 4.0 t Vy = 3.0 t
V = sqrt(V2^2 + Vy^2) = 5 t
Integrate Vx and Vy for the x and y locations vs. t.
Answered by
How do you do this?
How would you integrate them?
Answered by
hakin
intigrate
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