Ask a New Question

Question

A 4.3 kg particle starts from rest and moves a
distance of 3.6 m in 2.5 s under the action of
a single, constant force.
Find the magnitude of the force.
Answer in units of N.
15 years ago

Answers

MathMate
Use
S=ut+(1/2)at²
S=distance (3.6m)
u=initial velocity (=0)
a=acceleration (unknown) in m/s²
t=time in seconds (2.5 s)
Solve for a.

Use
F=ma to get the force,
m=mass in kg.
15 years ago

Related Questions

A particle starts at x=0 and moves along the x-axis with velocity v(t)=2t+1 for time t is less than... At t= 0, a particle starts from rest at x= 0, y= 0, and moves in the xy plane with an acceleration... At t= 0, a particle starts from rest at x= 0, y= 0, and moves in the xy plane with an acceleration... A particle starts from xi = 10 m at t0 = 0 and moves with the velocity graph shown in the graph belo... At t=0 , a particle starts at the origin with a velocity of 6 feet per second and moves along the x-... 4. A particle starts at the point (5, 0) at t = 0 and moves along the x-axis in such a way that at t... At t=0 a particle starts from rest at x=0, y=0 and moves in the xy plane with an acceleration a=(4.0... A 7.80 kg particle starts from rest and moves a distance of 8.90 m in 2.60 s under the action of a s... A particle, which starts from rest, covers a distance of 19.94 cm in the first 8.6 seconds. Find the... When a particle starts from rests and moves with constant acceleration then why its path is always a...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use