Use
S=ut+(1/2)at²
S=distance (3.6m)
u=initial velocity (=0)
a=acceleration (unknown) in m/s²
t=time in seconds (2.5 s)
Solve for a.
Use
F=ma to get the force,
m=mass in kg.
A 4.3 kg particle starts from rest and moves a
distance of 3.6 m in 2.5 s under the action of
a single, constant force.
Find the magnitude of the force.
Answer in units of N.
1 answer
1 answer