Question

A particle starts from rest and has an acceleration of 2m/s*2 for 10sec.After that, the particle travels for 30sec with constant speed and then undergoes a retardation of 4m/s*2 and comes back to rest. The total distance covered by the particle is?

Answer 1

x0 = 0

x1 = (1/2) 2 (100)
v1 = 2*10 = 20

x2 = x1 + 20 (30) = x1 + 600
v2 = x1 = 20

time retarding = t
0 = v2 - 4 t
so t = v2/4
then
x3 = x2+v2(v2/4)-(1/2)(4)(v2^2/16)