Asked by Kiersten
if sec theta = -13/5 on the interval(90,180), find the exact value of sin 2 theta
Answers
Answered by
bobpursley
if secTheta=-13/5, then cosTheta=-5/13
cos^2 + sin^2=1
sin^2=1-25/169=144/169
sinTheta=12/13 (in second quadrant, positive0
sin(2Theta)=2sinTheta*cosTheta=2(12/13)(-5/13)= you do it.
check my thinking
cos^2 + sin^2=1
sin^2=1-25/169=144/169
sinTheta=12/13 (in second quadrant, positive0
sin(2Theta)=2sinTheta*cosTheta=2(12/13)(-5/13)= you do it.
check my thinking
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