Asked by Sumathi
                Sin theta,cos theta,tan theta are in g.p. prove that cot^6 theta-cot^2 theta =1
            
            
        Answers
                    Answered by
            Steve
            
    since the ratio is constant,
cosθ/sinθ = tanθ/cosθ
cotθ = tanθ/cosθ
cot^2θ = secθ
cot^4θ = sec^2θ
cot^4θ = 1+tan^2θ
cot^6θ = cot^2θ+1
cot^6θ-cot^2θ = 1
    
cosθ/sinθ = tanθ/cosθ
cotθ = tanθ/cosθ
cot^2θ = secθ
cot^4θ = sec^2θ
cot^4θ = 1+tan^2θ
cot^6θ = cot^2θ+1
cot^6θ-cot^2θ = 1
                    Answered by
            Nayandhara
            
    I cannot able to understand the clear answer
    
                    Answered by
            Nayandhara
            
    Sorry I understand it so thanks
    
                    Answered by
            Anonymous
            
    I can understand clearly thanks u so much 
    
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