Asked by aisha
100mL of oxalic acid (H2C2O4) requires 35mL of 0.04M KMnO4 to titrate it to the endpoint. calculate the molarity of the oxalic acid.
Answers
Answered by
DrBob222
5C2O4^2- + 2MnO4^- ==> 2Mn^2+ + 10CO2
I know that doesn't balanced the equation and if you wish to add the H^+ on the left and H2O on the right I recommend it; however, the redox part is balanced and that is all that is needed to work the problem. Your prof may want you to completely balance the equation.
mols KMnO4 = M x L = ?
Using the coefficients in the equation above, convert mols KMnO4 to mols H2C2O4.
Then M H2C2O4 = mols H2C2O4/L H2C2O4. You know L and mols, solve for M.
I know that doesn't balanced the equation and if you wish to add the H^+ on the left and H2O on the right I recommend it; however, the redox part is balanced and that is all that is needed to work the problem. Your prof may want you to completely balance the equation.
mols KMnO4 = M x L = ?
Using the coefficients in the equation above, convert mols KMnO4 to mols H2C2O4.
Then M H2C2O4 = mols H2C2O4/L H2C2O4. You know L and mols, solve for M.
Answered by
Adeleke Matthew
0.1
Answered by
Adeleke Matthew
0.035
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