Question

The amount of oxalic acid (equ.wt.63) required to prepare 500ml of its 0.10 N solution is

Answer 1

Here is a very useful formula.
mL x N x mew = grams.
mL = millileters
N = normality
mew = milliequivalent weight
500 mL x 0.10 N x 0.063 = grams.
Solve for grams.