Asked by Ammu
The amount of oxalic acid (equ.wt.63) required to prepare 500ml of its 0.10 N solution is
Answers
Answered by
DrBob222
Here is a very useful formula.
mL x N x mew = grams.
mL = millileters
N = normality
mew = milliequivalent weight
500 mL x 0.10 N x 0.063 = grams.
Solve for grams.
mL x N x mew = grams.
mL = millileters
N = normality
mew = milliequivalent weight
500 mL x 0.10 N x 0.063 = grams.
Solve for grams.
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