A sample of oxalic acid, H2C2O4, is titrated with standard sodium hydroxide, NaOH, solution. A total of 45.2 mL of 0.12 M NaOH is required to completely neutralize 20.0 mL of the acid. What is the concentration of the acid?

Question

Concentration is Molarity, which is moles solute / liters solution.
Would the L of soln be 45.2 mL + 20.0 mL= 65.2 mL = 0.652 L?

And how do I find the moles solute?

Answer 1

VolumeAcid*Molarityacid=Volumebase*Molarity base

VolumeBase=45.1ml
MolarityBase=.12M
VolumeAcid=20ml
Solve for molarity acid.