Question

20.5 mL of oxalic acid,H2C2O4 were titrated with 0.800 M solution of lithium hydroxide. It took 40.0 mL of the base to reach the equivalence point. What is the molarity of the oxalic acid?
H2C2O4 + 2LiOH ==> LiC2O4 + 2H2O

moles oxalic acid = M x L.
moles LiOH = 2x moles oxalic acid (from the equation).
M LiOH = moles LiOH/L LiOH.

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