Asked by Amis
A sample of oxalic acid, H2C2O4, weighing 1.294 g is placed in a 100.0 mL volumetric flask, which is then filled to the mark with water. What is the molarity of the solution?
Answers
Answered by
DrBob222
Remember the definition of molarity.
M = # mols/L.
Convert 1.294 g H2C2O4 to mols.
Then #mols/0.1 L = ??M
M = # mols/L.
Convert 1.294 g H2C2O4 to mols.
Then #mols/0.1 L = ??M
Answered by
Brittany
would the moles be .014?
Answered by
DrBob222
Close. The # mols = 1.294/90.035 = 0.014406 which rounds to 0.01441. You have 4 significant figures in 1.294; therefore, you may have that many in the answer.
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