Asked by steven

4. A ball is thrown so that it just clears a 3m fence 18m away. If it left the hand 1.5m above the ground and at an angle of 60° with the horizontal, what was the initial velocity of the ball?
Answered by Henry
Range = Vo^2*sin(2A)/g = 18
A = 60o
g = 9.8 m/s^2
Vo = Initial velocity in m/s.
Solve for Vo.
Answered by Anonymous
14.628
Answered by bog
tangina naprepressure na ako:(

Answered by Anonymous
Nakakainis
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