Asked by Ralf miles
3. A ball is thrown into the air with an initial upward velocity of 46ft/s. Its height (h) in feet after t seconds is given by the function h = -16t^2 + 46t + 6. After how many seconds will the ball hit the ground?
A. 3
B. 4
C. 5
D. 6
I think D, if i'm wrong can one of you guy help me thanks
A. 3
B. 4
C. 5
D. 6
I think D, if i'm wrong can one of you guy help me thanks
Answers
Answered by
Steve
well, did you check it?
-16*36 + 46*6 + 6 = -294
So, stop guessing and do the math!
h = -2(8t^2-23t-3)
= -2(8t+1)(t-3)
So now what do you think?
-16*36 + 46*6 + 6 = -294
So, stop guessing and do the math!
h = -2(8t^2-23t-3)
= -2(8t+1)(t-3)
So now what do you think?
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