Asked by JJ

If a ball is thrown into the air with a velocity of 41 ft/s, its height (in feet) after t seconds is given by y = 41t − 16t^2. Find the velocity when t = 1.
Answered by Reiny
velocity = dy/dt

dy/dt = 41 - 32t

plug in t=1
There are no AI answers yet. The ability to request AI answers is coming soon!