Asked by JJ
If a ball is thrown into the air with a velocity of 41 ft/s, its height (in feet) after t seconds is given by y = 41t − 16t^2. Find the velocity when t = 1.
Answers
Answered by
Reiny
velocity = dy/dt
dy/dt = 41 - 32t
plug in t=1
dy/dt = 41 - 32t
plug in t=1
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.