Question

If a ball is thrown off a 123 m cliff at a speed of 18 m/s, how far from the base of the diff is the ball?

Givens:
Unknown:
Equation:
Substitute:
Solve:

Answer 1

Xo = 18 m/s. = Hor. velocity.

h = o.5g*t^2.
123 = 4.9t^2, t = 5.01 s. to reach gnd.

d = Xo*t = 18 * 5.01 = 90.2 m.