Asked by hheellpp

a 0.15 kg ball is thrown into the air & rises to a height of 20.0 m. how much kinetic energy did the ball initially have? ? ?
Answered by Henry
Vo^2 = Vf^2 - 2g*d.
Vo^2 = 0 -(-19.6)*20 = 392.
Vo = 19.8 m/s.
KE = 0.5m*V^2 = 0.075 * (19.8)^2 = 29.4
Joules.
Answered by hheellpp
thankss . what does the ^ mean tho ?
Answered by Josephine
to the power of...
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