Question
A ball is thrown into the air and its position is given by h(t)=−7.2t^2+26t+16 where h is the height of the ball in meters t seconds after it has been thrown. Find the maximum height reached by the ball and the time at which that happens.
____meters
____seconds
How do I solve this? It has nothing in common with the other problems in my work, nor is it something we've talked about.
It is due tonight, and I could use the help.
____meters
____seconds
How do I solve this? It has nothing in common with the other problems in my work, nor is it something we've talked about.
It is due tonight, and I could use the help.
Answers
max height is at the vertex of the parabola ... on the axis of symmetry
axis of symmetry ... t = -26 / (2 * -7.2)
solve for t , then plug into the equation to find h
axis of symmetry ... t = -26 / (2 * -7.2)
solve for t , then plug into the equation to find h