Asked by shiella
A ball is thrown so that the motion is defined by the equations x= 5t and y= 2+6t-4.9t^2, where x and y are expressed in meters and t is expressed in seconds. Determine (a) the velocity at t=1s, (b) the horizontal distance the ball travels before hitting the ground
Answers
Answered by
scott
the velocity is constant in the x-direction ... dx/dt = 5 m/s
the velocity in the y-direction is time dependent ... dy/dt = 6 - 9.8 t m/s
(a) plug in t = 1 , and add the x and y velocity vectors
(b) set y=0 and solve for t , plug the result into the x equation
the velocity in the y-direction is time dependent ... dy/dt = 6 - 9.8 t m/s
(a) plug in t = 1 , and add the x and y velocity vectors
(b) set y=0 and solve for t , plug the result into the x equation
Answered by
Christian
a. 5.88 m/s
b. 7.5 m
b. 7.5 m
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