Asked by Rowan
A ball is thrown so that its motion is defined by the equations:
x = 5t; y = 2 + 6t - 4.9t2, where and x and y are in meters and t is in seconds. Determine:
1. The velocity of the ball at any time t
2. The initial position and velocity of the ball
3. The velocity of the ball at time = 1.1 second
4. The horizontal distance the ball travels before it hits the ground.
5. The time at which the ball hits the ground
6. The magnitude and direction of the velocity vector when the ball hits the ground
x = 5t; y = 2 + 6t - 4.9t2, where and x and y are in meters and t is in seconds. Determine:
1. The velocity of the ball at any time t
2. The initial position and velocity of the ball
3. The velocity of the ball at time = 1.1 second
4. The horizontal distance the ball travels before it hits the ground.
5. The time at which the ball hits the ground
6. The magnitude and direction of the velocity vector when the ball hits the ground
Answers
Answered by
oobleck
#1. v = 5i + (6-9.8t)j
#2. set t=0
#5 find t when y=0
the rest should be no trouble
#2. set t=0
#5 find t when y=0
the rest should be no trouble
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