Asked by Zach
A ball is thrown up with an initial velocity of 32 feet per second. How many seconds will it take for the ball to return to the ground using the formula h=vt-16t^2?
Answers
Answered by
Reiny
in h = 32t - 16t^2 , you are finding t when h = 0
32t - 16t^2 = 0
16t(2 - t) = 0
t = 0 or t = 2
it will take 2 seconds to return
(the t=0 gives you the initial height of 0)
32t - 16t^2 = 0
16t(2 - t) = 0
t = 0 or t = 2
it will take 2 seconds to return
(the t=0 gives you the initial height of 0)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.