Asked by Connor Steelwood
A ball is thrown from the top of a 50-ft building
with an upward velocity of 24 ft/s. When will it
reach its maximum height? How far above the
ground will it be? Use the equation
h(t)= -16t^2 + 24t + 50
with an upward velocity of 24 ft/s. When will it
reach its maximum height? How far above the
ground will it be? Use the equation
h(t)= -16t^2 + 24t + 50
Answers
Answered by
oobleck
as with any parabola "at^2+bt+c" the vertex is at
(-b/2a, c - b^2/4a)
(-b/2a, c - b^2/4a)
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