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L.Bianchessi
Questions (38)
If trypsin and chymotrypsin become activated within the pancreas and then are released in their active forms into the
0 answers
364 views
If trypsin and chymotrypsin become activated within the pancreas and then are released in their active forms into the
0 answers
461 views
A classmate who has been standing still for several hours working on a laboratory experiment suddenly faints. Based on what was
1 answer
559 views
One liter of arterial blood at sea level contains approximately 3 mL of dissolved oxygen and 197 mL of oxygen bound to
4 answers
992 views
Calculate the percent ionizationof a 0.15 M benzoic acid solution in pure water Nd also in a solution containing 0.10M sodium
1 answer
4,180 views
Find the domain of f(x) = 1/ (square root 2x^2-7x-15)
I tried setting 2x^2-7x-15 greater or equal to zero but I don't know where
1 answer
477 views
Find the maximum value, and where it occurs for eAch function.
G(x)= (square root -x^2+4x+12)
3 answers
443 views
A town has a population which is growing linearly. In 1970 its population was 36,000 while in 1985 its population was 63,000.
1 answer
605 views
The point (5,-2) lies on the graph of y=f(x), and assume f^-1(x) exists. Find the corresponding point on eAch graph.
A).
3 answers
1,135 views
The point (5,-2) lies on the graph of y=f(x), and assume f^-1(x) exists. Find the corresponding point on eAch graph.
A).
0 answers
459 views
The point (5,-2) lies on the graph of y=f(x), and assume f^-1(x) exists. Find the corresponding point on eAch graph.
A).
0 answers
960 views
find the point on the line y=2x-1 which is closest to the point (2,-1).
I used distAnce formula and got D= (square root 5x^2 -4x
1 answer
1,055 views
Let P(x,y) be a point on the curve y=16-x^2 and let A be the point directly below P on the x axis. If O is the origin, find the
1 answer
545 views
find the ph of 0.100M NaC2H3O2 solution.
do i just write an equation and solve for x NaC2H3O2 +H2O= Na2O + HC2H3O2- 0.100 0 0 so
2 answers
727 views
find the ph of 0.100M NaC2H3O2 solution.
do i just write an equation and solve for x NaC2H3O2 +H2O= Na2O + HC2H3O2- 0.100 0 0 so
0 answers
559 views
A 0.035 M solution of a weak base has a pH of 10.88. What is the Kb for the acid?
Where Di I even begun**???
1 answer
743 views
Write two reactions for NaHCO3, reacting with water in one NaHCO3 is acting as acid the other as a base. Is 0.10M solution going
1 answer
550 views
Let f(x)=3x-4x^2
Find f o f o f So... F(f(x)) I got a really big answer..... I think I might have done something wrong when doing
1 answer
346 views
Let f(x)=3x-4x^2
Find f o f o f So... F(f(x)) I got a really big answer..... I think I might have done something wrong when doing
0 answers
865 views
Determine whether each cation is acidic or pH neutral. For those cations that are acidic, write an equation that shows how the
1 answer
2,053 views
Determine whether each cation is acidic or pH neutral. For those cations that are acidic, write an equation that shows how the
0 answers
731 views
Determine whether each cation is acidic or pH neutral. For those cations that are acidic, write an equation that shows how the
1 answer
1,406 views
Determine whether each anion is basic or neutral. For those that are basic, wrote an equation that shows how an anion acts as a
0 answers
1,115 views
Find the pH of each mixture of acids.
0.020 M HBr and 0.015 M HClO4. They are both strong acids Si they dissociate completely. Si
1 answer
4,586 views
Find the pH of each mixture of acids.
0.115 M HBr and O.125 M HCHO2. I TRIED DOING THIS PROBLEM THE SAME WAY AS THE ONE BEFORE
1 answer
3,408 views
Find the pH of mixture of acids. 0.185 M in HCHO2 and 0.225 M in HC2H3O2
Im using an ice chart of weak acid and putting in strong
3 answers
4,218 views
Find the pH of mixture of acids.
0.185 M in HCHO2 and 0.225 M in HC2H3O2 Im using an ice chart of weak acid and putting in strong
4 answers
1,239 views
The value of Kw increases with increasing temperature. Is the autoionization of water endothermic or exothermic?
In thinking its
2 answers
2,565 views
How many significant figures are in 0.0?
And how about 0.00?
1 answer
473 views
This is probably easier then my making it but...
Calculate the ph of a forming acid solution that contains 1.35% forming acid by
3 answers
1,028 views
A burning log, light from flashlight, car in motion, are examples of what type of energy?
1)potential 2)thermal 3)kinetic
0 answers
362 views
According to the second law of thermodynmics..a) cold moves to hot
B) low pressure moves to high pressure C) wet moves to dry D)
0 answers
436 views
Ranking equilibrium constants from largest to smallest according to an image?Ethene (C2H4) can be halogenated by the following
10 answers
10,431 views
A chemist trying to synthesize a particular compound attempts two different synthesis reactions. The equilibrium constants for
1 answer
3,084 views
Find the slope.
(3,1/3) and (3+h, 1/(3+h)) I think I get -1/ 3(3+h) ???
1 answer
285 views
The activity of carbon 14 in living tissue is 15.3 disintegrations per minute per gram of carbon. The limit for reliable
4 answers
1,175 views
measurements of carbon 14 taken from linen wrappings of the book of isaiah from the dead sea scrolls indicate that the scrolls
2 answers
3,194 views
Im a freshman in college and I just took Chem1, Trig, and Drama (12units). I am planning on taking Chem2, Pre-Calc, and Art1 for
2 answers
1,141 views
Answers (65)
oh, okay that makes sense its like a conversion factor. Thank you!
figured it out. but need help on my other question please!:)
Average rate of disappearance just means slope! So... (0.535-0.268)M / 0-520sec =5.13 X 10^-4Ms^-1 Tada!
160Angstrom
S=5
You could probably set up a proportion. so.... 0.160/x= 0.205/1.5ppm Solve for x.
Cr+3, Na+, I2, F2 Oxidized- lose electrons
Volume =length x width x height You just multiply all three numbers to get what ever number m^3.
Well since sulfuric acid is a strong acid it dissociate completely so you just do the -log(0.10) =pH
Well 1min =60 sec ... So 60 sec +25 sec= 85sec
2cm.... 2cm x 4cm x3cm=24cm^3
285 miles to travel between two cities
Example--Difference of squares: (x^2 + 5x-6) = (x+6)(x-1) 1. Write an x in both parenthesis 2. Find factors of 6. (6x1 or 3x2) 3. The inner (6x) plus the outer (-1x) should equal the middle term 5x Or you could foil. Trinomial: (a+b)(a^2-ab+b^2)
The ice bath one would take longer because it takes more energy for the solution in the flask to form products thus, the activation energy is higher making the reactants need energy so it is endothermic.
That's true but you should include how the temperature affected the rate and which way the equilibrium shifted and how the color change tells you which way it shifted. When you heat the test tube the solution turned a dark purple/blue color. And when you
Answer: (square root 1-25x^2 )/ 5x
Is it set equal to anything?
No it would not. You convert 536.8 g to ml by using the density. You get 753 so no you cannot fit it into a 750 ml flask.
Well you use the area of a square formula. Do. You do (3x+2)^2=Area Get it?
Well if your cheap calculator has a exponent. You could do 2.72^-4.7 You get 0.0090683057 It's pretty close!
Is the 5 an exponent?
Cos inverse of 1/4 =2t So do cos inverse of 1/4=75.52... So... 75.52...= 2t Solve for t. T=37.76..
Well... You know that KOH is a strong base... So it ionizes completely. KOH----> K+ +OH- So you need the molarity of KOH... So.. 1.100g/.5500 L x 1mol/56.11g KOH = 0.0356 M KOH So since KOH is strong... Concentration KOH, K+, and OH- = 0.0356M
The cost equity. Because... Cost debt+ cost equity= WACC
Well you subtract the 16 to get your equation equal to one. Do x^2/16 + y^2/4=1 Your center is 0,0 Your eclipse would be horizontal. Do when graphing put a point at (0,0) then go 4 spaces in the negative and positive direction on the x-axis. Then go up 2
Well we can graph the points and form a triangle. We can then find the distance between each point(side). And if two sides have the same distance we know that the triangle is isosceles. Distance between AC: D=square root of (5-0)^2 +(2-1)^2 D=radical 26
Do you mean ax^2+ bx+c=0 ??
The acid on the left has a conjugate base on the right. H20 is acting as base, and H3O+ conjugate acid. It's pretty much the opposite.
You would add H2O to the acid and determine the products from a double reaction. The acid who gives the H+ up is the acid and the one who accepts it is the base. You look over at the products and those are called the conjugates. Do for example... 1) HSO4-
You would need the chemical formula for plant food to see what it produces as products.
Na+4 doesn't exist because sodium can only give away one electron because that's all it has. But maybe you are trying to say... Na3PO4---> 3Na^+ + PO4^-3
Oh okay yeah I didn't add the 5.77x10^-3 to the weaker acid. So I determine concentration of stronger acid then put that H concentration into the weaker acid then I determine the concentration of the H of CH3COOH and get 7.02x10^-4 and add the H+
you would do a conversion factor. 50g of H2SO4 x 1mol sulfuric acid/ molar mass of sulfuric acid x grams of H2/ 1mol H2 You get grams of H2. Get it?
YOU COULD SEE THE GRAPH BY GOING TO GOOGLE AND ENTERING IN WOLFRAM ALPHA A WEBSITE AND ENTER IN THE EQUATION. THEY USUALLY WILL GRAPH IT FOR YOU BUT YOU NEED TO DETERMINE THE PERIOD, AND ETC. STUFF FOR YOUR GRAPH.
WELL FOR SIN AND AND CSC YOU KNOW THAT THE INTERVAL HAS TO BE BETWEEN 0
So you get 0.01304 mol HCL. YOU GET 0.483GRAMS OF CALCIUM HYDROXIDE.
Determine your moles of HCl. Then use your equation to convert moles of HCl to moles of Ca(OH)2 then to grams of the calcium hydroxide. The ratio would be 2Mol HCL to 1mol of Ca(OH)2
Yes.
I got concentration of HCOOH rxn to be 5.77X10^-3. And the CH3COOH rxn to have concentration of 2.01X10^-3. I added those together to get 7.78X10-3. What do you mean add to ka expression? I keep getting 1.35 now.
Oh, okay so increasing the kw makes the reaction produce more OH- and H+ so energy must be increasing on the reacting side to produce a endothermic reaction meaning energy is being absorbed to obtain a high temperature for the kw. Ahh...I get it! Thank
I plugged in 3x-72=___ (set them equal to 420,660,780,1020) Answer:44,124,164,244,284 degrees
It you cannot determine the concentration of the mixture by forming a double replacement became you form products that are the same as the reacting because you are mixing two acids.
44&124degrees
Well I haven't done trig in a long time but u believe... You divide the 2 to each side to get Cos(3x-72)=1/2 Then do the inverse to both sides to get rid of the cos and end with 3x-72=60 degrees So x= 44 degrees Cosine is positive in quad1&4 So 44degrees
Oh and the answer would be y=-1/5x
Oh, you just divide the negative to each side and get y=5x-2. Then use y-y1=m(x-x1) y-(-2)=-1/5(x-10) Then solve.
I just wrote mine in terms of the concentration of the thiosulfate. Pretty much I isolated the variable I was trying to find. :) same thing though!
Solve for y for the given equations. Putting it in y=mx+b form. Then do the negative reciprocal of the slope from the given equation. After that use the point slope formula to calculate the new equation using the given point and your new slope. Do you get
Yes, exactly! Since we are diluting we can use M1V1=M2V2. So Concentration of thiosulfate X Amt.(volume) of added thiosulfate = (75ml)total volume X the Concentration of the new concentration of thiosulfate in the flask(what you are trying to find) The
I did this same experiment a couple weeks ago. We are measuring the amount of time it takes for the thiosulfate to run out. So to calculate the concentration of the thiosulfate ion. You can multiply the milliliters of thiosulfate in whatever trail you are
