how to find the pH of 0.10 M H2SO4 ??

2 answers

Well since sulfuric acid is a strong acid it dissociate completely so you just do the -log(0.10) =pH
To add a bit of information here, H2SO4 has TWO H atoms. The first one is a strong acid and (H^+) is due largely to the ionization of the first acid. The second H is not a strong one and it has a k2 but it is relatively large as k values go (about 0.012). The second H contributes a small amount. I've worked through to see how much and the answer is about 0.0098 so the final concn H^+ is 0.1+0.0098 = about 1.1M. The main thing I want to point out hee is that it is NOT 2 x 0.1 BUT the second H does contribute a small amount.