Ask a New Question

Question

solve for t:

0=4sin(2t)cos(2t)-sin(2t)
13 years ago

Answers

drwls
0 = sin(2t)[4 cos(2t) -1]

There are two possible solutions:
sin(2t) = 0
(which leads to t = 0 or pi/2)
and
cos(2t) = 1/4
which leads to other values of t.
t = (1/2)cos^-1(1/4)
13 years ago
Lucy
if cos2t=1/4 then t= what??
13 years ago
L.Bianchessi
Cos inverse of 1/4 =2t
So do cos inverse of 1/4=75.52...
So...
75.52...= 2t
Solve for t.
T=37.76..
13 years ago

Related Questions

Solve 4sin^2x + 4(squareroot of 2)cosx -6 for all real values of x. Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x. My answer: (pi/4)+2(pi)k, (7pi/4)... Solve step by step 4sin^2x = 3cos^2x solve the equation 1+4sin(x)=4cos^2(x) ((4sin(atan(4/3))-4sin(0)))-(-3cos(atan(4/3))-(-3cos(0)))+((-3cos(pi/2)-(-3cos(atan(4/3))))-(4sin(pi... Solve the equation 4sin x = e^x on the interval (0, 1). Correctly rounded to two decimal places, x= solve for x: 4sin^2x= 4cosx+1 Solve 2cos^2(x) + 4sin(x)-3 = 0, giving all solutions in the interval 0 ≤ x ≤ 2π Solve 4sin(pi/4x) = 3 for the four smallest positive solutions Solve the equation 4sin^2 thiter +4cos thiter=5 for 0 degrees<=thiter<=360 degrees, give your answer...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use