Asked by Lucy
solve for t:
0=4sin(2t)cos(2t)-sin(2t)
0=4sin(2t)cos(2t)-sin(2t)
Answers
Answered by
drwls
0 = sin(2t)[4 cos(2t) -1]
There are two possible solutions:
sin(2t) = 0
(which leads to t = 0 or pi/2)
and
cos(2t) = 1/4
which leads to other values of t.
t = (1/2)cos^-1(1/4)
There are two possible solutions:
sin(2t) = 0
(which leads to t = 0 or pi/2)
and
cos(2t) = 1/4
which leads to other values of t.
t = (1/2)cos^-1(1/4)
Answered by
Lucy
if cos2t=1/4 then t= what??
Answered by
L.Bianchessi
Cos inverse of 1/4 =2t
So do cos inverse of 1/4=75.52...
So...
75.52...= 2t
Solve for t.
T=37.76..
So do cos inverse of 1/4=75.52...
So...
75.52...= 2t
Solve for t.
T=37.76..
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