Solve step by step

Question

4sin^2x = 3cos^2x

Answer 1

4sin^2x = 3(1-sin^2x)
4sin^2x = 3 - 3sin^2x
7sin^2x = 3
sin^2x = 3/7
sinx = ±√(3/7), so x is in any of the 4 quadrants

In first quadrant I get x = 40.9 degrees
in II, x = 180 - 40.9
in III, x = 180+40.9
in IV, x = 360-40.9