Asked by Caitlin
Solve step by step
4sin^2x = 3cos^2x
4sin^2x = 3cos^2x
Answers
Answered by
Reiny
4sin^2x = 3(1-sin^2x)
4sin^2x = 3 - 3sin^2x
7sin^2x = 3
sin^2x = 3/7
sinx = ±√(3/7), so x is in any of the 4 quadrants
In first quadrant I get x = 40.9 degrees
in II, x = 180 - 40.9
in III, x = 180+40.9
in IV, x = 360-40.9
4sin^2x = 3 - 3sin^2x
7sin^2x = 3
sin^2x = 3/7
sinx = ±√(3/7), so x is in any of the 4 quadrants
In first quadrant I get x = 40.9 degrees
in II, x = 180 - 40.9
in III, x = 180+40.9
in IV, x = 360-40.9
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.