The triangle has vertices A(0,1),B(1,6) and C(5,2).Prove that the triangle is isosceles.

Answer 1

Well we can graph the points and form a triangle. We can then find the distance between each point(side). And if two sides have the same distance we know that the triangle is isosceles.
Distance between AC:
D=square root of (5-0)^2 +(2-1)^2
D=radical 26

distance between AB:
D= square root (1-0)^2 +(6-1)^2
D=radical 26

Distance between BC:
D=square root (5-1)^2 +(2-6)^2
D=4 radical 2

Tada!