Question
Calculate pH for strong base solution: 1.100 g of KOH in 550.0 mL of solution
Answers
DrBob222
1.1g/molar mass KOH = mol KOH = mols OH^-
M= mols/L, then convert to pOH and to pH.
M= mols/L, then convert to pOH and to pH.
L.Bianchessi
Well...
You know that KOH is a strong base... So it ionizes completely.
KOH----> K+ +OH-
So you need the molarity of KOH...
So..
1.100g/.5500 L x 1mol/56.11g KOH = 0.0356 M KOH
So since KOH is strong...
Concentration KOH, K+, and OH- = 0.0356M
pOH=-log(0.0356)
pOH= 1.45
pOH+pH=14
pH= 14-1.45
So pH=12.55 Tada!
You know that KOH is a strong base... So it ionizes completely.
KOH----> K+ +OH-
So you need the molarity of KOH...
So..
1.100g/.5500 L x 1mol/56.11g KOH = 0.0356 M KOH
So since KOH is strong...
Concentration KOH, K+, and OH- = 0.0356M
pOH=-log(0.0356)
pOH= 1.45
pOH+pH=14
pH= 14-1.45
So pH=12.55 Tada!