Calculate pH for strong base solution: 1.100 g of KOH in 550.0 mL of solution

Answer 1

1.1g/molar mass KOH = mol KOH = mols OH^-
M= mols/L, then convert to pOH and to pH.

Answer 2

Well...
You know that KOH is a strong base... So it ionizes completely.
KOH----> K+ +OH-

So you need the molarity of KOH...
So..
1.100g/.5500 L x 1mol/56.11g KOH = 0.0356 M KOH

So since KOH is strong...
Concentration KOH, K+, and OH- = 0.0356M

pOH=-log(0.0356)
pOH= 1.45

pOH+pH=14
pH= 14-1.45
So pH=12.55 Tada!