Question
For the following strong base solution 0.40 M NaOH, determine [OH-] and [H30+].
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Answers
DrBob222
0.4M KOH = 0.4M OH^- and
pOH = -log 0.4
pOH = 0.398 and
pH + pOH = pKw = 14
pH = 13.6
pOH = -log 0.4
pOH = 0.398 and
pH + pOH = pKw = 14
pH = 13.6