Answers by visitors named: JAC OB254

P=Q+3r/T P-Q=3r/T T(P-Q)=(3r/T)T PT-QT=3r r=(PT-QT)/3

3 years ago

(a) let the horizontal distance be x and the vertical height be y cos 20= x/400 x=400cos 20 (use a calculator) (b) sin 20= y/400 y=400sin 20 (use a calculator)

3 years ago

Maximum height= 1/2gt^2 20= 1/2×10t^2 20=5t^2 4=t^2 square root both sides t=2 seconds R=ut R=15×2 R=30m

3 years ago

s=1/2gt^2 20= 1/2×10t^2 20=5t^2 4=t^2 square root both sides t=2 seconds R=ut R=15×2 R=30m

3 years ago

972/27 =36 tickets

3 years ago

3/10 and 18/60

3 years ago

y is directly proportional to x y=kx where k is a constant 7=2k k=7/2 therefore, y=7/2x 21=7/2x x=21×2/7 x=6

3 years ago

(a) nth term=a+(n-1)d 10=a+(3-1)d 10=a+2d a+2d=10....eqn (i) -10=a+(5-1)d -10=a+4d a+4d=-10....eqn (ii) a+2d=10 a+4d=-10 solve by elimination method -2d=20 d=-10 substitute d=-10 in the eqn a+2d=10 a+(2×-10)=10 a-20=10 a=30 therefore, the first term is 30...

3 years ago

It is the rate of change of velocity of a body under the influence of gravitational force.

3 years ago

CaCO3(s) + 2HCl(aq)> CaCl2(aq) +CO2(g)+H2O(l) RFM of CaCO3 =(2×40)+12+(3×16) =80+12+48=140 No of moles of CaCO3 that reacted =2/140 =1/70 moles mole ratio of CaCO3 to CO2 is 1:1 therefore, the no of moles of CO2 produced= 1/70 moles Molar gas volume at ST...

3 years ago

C=2#r where # is pie=22/7 C=2×22/7×2x×2x =2×22/7×4x^2 =44/7×4x^2 =176x^2/7 =25 1/7x^2 cm^2

3 years ago

Multiply numerator and denominator by 1000 =456×36/120 =456×3/10 =1368/10 =136.8

3 years ago

Express 10500 as a product of its prime factors 10500= 2×2×3×5×5×5×7 =2^2×3×5^3×7 since we need a perfect square, the numbers 3, 5^3 and 7 don't satisfy the condition. the missing numbers are 3, 5 and 7 p=3×5×7 p=105

3 years ago

Let the no of games that he lost be x no of games won= 5-x points awarded= 3(5-x)= 15-3x points deducted= 2x 15-3x+2x=5 15-x=5 -x=5-15 -x=-10 x=10 therefore, he lost 10 games

3 years ago

Sorry, I have done your question wrongly. Avoid the above workings and follow this new workings. METHOD 1 Let the number of games lost be x games won=5-x points awarded= 3(5-x)=15-3x points deducted= 2x points deducted must be subtracted from points award...

3 years ago

15-3=12 dish soaps

3 years ago

CaCO3(s)+ 2HCl(aq)> CaCl2(aq)+CO2(g)+H2O(l) RFM of CaCO3= 40+12+(3×16)= 40+12+48= 100 no of moles of CaCO3= 25/100 =0.25 moles from the equation, mole ratio of CaCO3 to CaCl2 is 1:1 therefore, the number of moles of calcium chloride= 0.25 moles

3 years ago

3y=2x+6 y=2/3x+2 gradient=2/3 tan ¤°= opposite/adjacent where ¤° is the angle in degrees ¤=33.7°

3 years ago

Let the numbers be x and y x+y=14....eqn(i) xy=40....eqn(ii) from eqn(i), y=14-x substitute y=14-x in eqn(ii) x(14-x)=40 14x-x^2=40 x^2-14x+40=0 solve using factorization method x^2-4x-10x+40=0 x(x-4)-10(x-4)=0 (x-4)(x-10)=0 x=4 or x=10 when x=4, y=14-4=1...

3 years ago

y=x^2(x+2)^3 (x+2)^3= (x+2)(x+2)(x+2) =(x^2+4x+4)(x+2) =x^3+2x^2+4x^2+8x+4x+8 =x^3+6x^2+12x+8 =x^2(x^3+6x^2+12x+8) =x^5+6x^4+12x^3+8x^2

3 years ago

-Place the mixture in a beaker and cover it with a watch glass. -Heat the mixture. Iodine vapour collects on the watch glass leaving lead sulphate in the beaker. -Stop heating when there is no further change. -Remove the watch glass and allow it to cool f...

3 years ago

Find the GCD of 70 and 525 70=2×5×7 525=3×5^2×7 GCD=5×7=35 therefore, the square plot measures 35 feet by 35 feet

3 years ago

Re_write the unit vectors in terms of column vectors, i.e, 6i-8j= (6 -8) -8i+3j= (-8 3) 26i+19j= (26 19) aA+bB+C=0 a(6 -8)+b(-8 3) +(26 19)=0 (6a -8a)+ (-8b 3b) +(26 19)=0 6a-8b+26=0 -8a+3b+19=0 6a-8b=-26....eqn(i) -8a+3b=-19 ....eqn(ii) solve using elimi...

3 years ago

1 dozen=12 3 dozens=?? =3×12 =36 cookies 36 cookies=13/4 cups 144 cookies=?? =144/36×13/4 =13 cups

3 years ago

1) juice=1/3 remainder=1-1/3=2/3 water=1/4 of 2/3 =1/6 2) soft drinks= 1-(1/3+1/6) =1-1/2 =1/2 1/2 of 48 =24 students

3 years ago

185+9×35 185+315 500 jellybeans

3 years ago

Let the number of mangoes be m Number of apples= 2/3m since 40% is for oranges, then 60% is for both apples and mangoes total no of apples and mangoes= m+2/3m=5/3m 60%=5/3m 100%=?? =100/60×5/3m =25/9m total fruits is 25/9m % of mangoes= m/(25/9m)×100 =1/(...

3 years ago

F=ke, where; F is force, k is spring constant and e is extension k=F/e k=40/0.03 k=4000/3 N/m when e=5cm=0.05m then, F=ke =4000/3×0.05 =66.667N when F=100N then, e=F/k =100/(4000/3) =0.075m=7.5cm

3 years ago

C=#D therefore, D=C/# =110.6/(22/7) =110.6×7/22 =35.19 =35.2mm

3 years ago

F=ke, thus k=F/e k=15/0.06 k=250N/m when e=25mm=0.025mm then, F=250×0.025 =6.25N

3 years ago

16-2(15-1) 16-2(14) 16-28 =-12

3 years ago

Time=distance/speed =6/3×10^8 =2×10^-9seconds

3 years ago

a) A=#r^2 =22/7×3.5×3.5 =38.5cm^2 b) curved surface area=2#rh =2×22/7×3.5×20 =440cm^2 c)area of the hemispherical part= 2#r^2 =2×22/7×3.5×3.5 =77cm^2 total surface area= 38.5+440+77 =555.5cm^2

3 years ago

Let Amina's age=x Ado=4x x+4x=20 5x=20 x=4 thus, Amina is 4 years old and Ado is 16 years old 16-4=12 years

3 years ago

Relative density of a substance= density of that substance/ density of water 7.8=density of steel/ 1000 density of steel=7.8×1000 =7800kg/m^3 volume=10×10×10 =1000cm^3 1000/1000000= 0.001m^3 mass=density×volume =7800×0.001 =7.8kg

3 years ago

Are waves that require a material medium for transmission.

3 years ago

LCM of 9, 15 & 15 is 45 1/9×45=5 2/15×45=6 3/15×45=9 1/9, 2/15, 3/15

3 years ago

Let the original number of bags be b new number of bags after the discount= 160/100b =1.6b total price for b bags before discount= 40b 100%=40b 144%=?? 144/100×40b =57.6b this is the price after the discount price of each bag during sale= 57.6b/1.6b =$36...

3 years ago

(a) v^2=u^2-2gs but v=0 0=20^2-(2×10×s) 0=400-20s 20s=400 s=20m (b) v=u-gt but v=0 0=20-(10×t) 0=20-10t 10t=20 t=2 seconds (c) v=u+gt when the stone reaches the maximum height, it returns and experiences free fall and u becomes zero (u=0m/s) v=0+10×2 v=20...

3 years ago

sin 30= x/36 x=36sin 30 x=18km 18-7=11km =11km east from the starting point

3 years ago

P=2(l+w) =2(1750+1500) =2(3250) =6500m 1000m=1km 6500m=?? =6500/1000 =6.5km

3 years ago

volume of the tank =66×35×45 =103,950cm^3 rate= 103950cm^3/18 min =5775cm^3/min

3 years ago

Six hundred and ninety one and four tenths

3 years ago

nth term=a+(n-1)d 10=a+(4-1)d 10=a+3d a+3d=10....eqn(i) 16=a+(7-1)d 16=a+6d a+6d=16....eqn(ii) a+3d=10 a+6d=16 solve using elimination method -3d=-6 d=2 a+3×2=10 a+6=10 a=4 Sn=n/2[2a+(n-1)d] =9/2[2×4+(9-1)2] =9/2[8+16] =9/2×24 =108

3 years ago

Molecular mass of gas x=7×2=14

3 years ago

F=ma a=F/m a=8/2 a=4m/s^2 F=(2+1)4 F=12N

3 years ago

(13-4)/(3-0) 9/3=3

3 years ago

80000/800=100

3 years ago

Let the number of boys be x girls=x+40 girls left the hall= 2/5(x+40)= 2/5x+16 boys left the hall= 1/3x girls remained in the hall= x+40-(2/5x+16) =x+40-2/5x-16 =3/5x+24 boys remained in the hall= x-1/3x=2/3x 3/5x+24=2/3x+18 24-18=2/3x-3/5x 6=1/15x x=6×15...

3 years ago

Let the cost of one pen=x 2 pens=2x file=2(2x) =4x 4x:x =4:1

3 years ago

Let the money Michael had first=x Bryant=60/100x= 3/5x let the bill paid for lunch=y Bryant=25/100y= 1/4y Michael=75/100y= 3/4y 3/5x-1/4y=56 12x-5y=1120 ....eqn(i) x-3/4y=25/100x x-3/4y=1/4x 4x-3y=x 3x-3y=0....eqn(ii) solve by elimination method by multip...

3 years ago

(a) Let the number of pencils bought be x Ruler=x+7 cost of pencils=0.7x cost of rulers= 0.4(x+7)=0.4x+2.8 0.4x+2.8=0.7x-1.1 2.8+1.1=0.7x-0.4x 3.9=0.3x x=13 number of pencils bought= 13 (b) number of rulers bought=13+7=20 cost=20(0.40) =$8.00

3 years ago

0.2

3 years ago

Sn=n/2[2a+(n-1)d] =11/2[2×2+(11-1)3] =11/2[4+30] =11/2×34 =187

3 years ago

14-(-3)^2 14-9 =5

3 years ago

2SO2(g)+O2(g)>2SO3(g) RFM of SO2= 32+2×16=64 no of mole of SO2 =96/64=1.5moles mole ratio of SO2 to SO3 is 2:2, thus no of moles of SO3 is 1.5moles 1 mole at STP=22.4Litres 1.5 moles=?? =1.5×22.4 =33.6 Litres

3 years ago

They neither gain nor lose electrons and so their outermost energy level is full.

3 years ago

Transmission of impulses

3 years ago

120 what has tempted you to ask such a question you could use a calculator or mind?

3 years ago

-7-5=-12

3 years ago

Where the car maintains a constant speed, that is the maximum speed. v=u+at but u=0m/s since the car starts from rest. v=0+(4×5) v=20m/s maximum speed= 20m/s

3 years ago

1hr>30sec from mon 0445hr to fri 1845hr is 4 days 14 hours 4×24+14=110 hours 1hr=30sec 110hrs= 110×30 =3300sec 3300/3600=11/12hr 11/12×60=55 min 1845hr-55min =1750hrs =5:50p.m

3 years ago

No of moles= molarity×volume =0.85×0.4 =0.34moles RFM of CuSO4= 64+32+4×16= 160 mass=no of moles×RFM =0.34×160 =54.4g

3 years ago

2/5×55=22km 22km=1 litre 55km=?? =55/22 =2.5 litres

3 years ago

(a) 250cm^3=1.4g 1000cm^3=?? =1000/250×1.4 =5.6g/dm^3 molarity=concentration(g/dm^3)/ RFM RFM of KOH=39+16+1=56 Molarity=5.6/56 =0.1M=0.1mol/dm^3 (b) H2SO4(aq)+ 2KOH(aq)> K2SO4(aq)+ 2H2O(l) moles of 25cm^3 of KOH=25/1000×0.1 =0.0025 moles mole ratio of KO...

3 years ago

Longitude difference=45-15 =30° 1°=4 min 30°=?? =30×4= 120 min 120/60= 2 hours since Nigeria is to the west of Ethiopia, subtract 2 hours from 5:00p.m 5:00-2:00 =3:00p.m.

3 years ago

the expression is in the form of ax^2+bx+c, where a=9, b=t and c=16 thus, b^2=4ac t^2=4×9×16 t^2=576 t=24

3 years ago

93×7=651 points

3 years ago

2KClO3(s)>2KCl(s)+3O2(g) RFM of KClO3 =39+35.5+3×16 =122.5 moles of KClO3 =29.4/122.5 =0.33moles mole ratio of KClO3 to O2 is 2:3 moles of O2 =3/2×0.33= 0.495moles mass=moles×molar mass =0.495×16 =7.92g 1 mole at STP=22.4dm^3 0.495 moles=?? =0.495×22.4 =1...

3 years ago

2Li(s)+2H2O(l)->2LiOH(aq)+H2(g) RAM of Li=7 moles of Li=3/7 moles mole ratio of Li to H2 is 2:1 moles of H2 =1/2×3/7=3/14 moles mass=moles×molar mass =3/14×2 =0.429g 1mole at STP= 22.4dm^3 3/14moles=?? =3/14×22.4 =4.8dm^3

3 years ago

a

3 years ago

(-2,3)+(2,3) =(0,6)

3 years ago

Find the cube root of 512 =8 inches

3 years ago

I don't have a lot of money, but if I had a lot of money, I would have travelled.

3 years ago

A=P(1+r/100)^n =650(1+4/100)^3 =731.16 I=A-P =731.16-650 =81.16

3 years ago

11/8 /(6) 11/48

3 years ago

They are not the same

3 years ago

Potential energy is lost while kinetic energy is gained.

2 years ago

The height of the tree above the boy is 12-1.4=10.6 Using tan#= opposite /adjacent where # is the angle of elevation tan#=10.6/10 hence #= 46.67 degrees

2 years ago

A number is divisible by 9 if the sum of its digits is 9 or a multiple of 9 3+7+1=11 The next multiple of 9 nearer to 11 is 18 thus, 18-11=7

2 years ago

JAC OB254

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