Asked by Veronica
A 2kg brick is at rest on a table. It requires a force of 8N to set the brick sliding. A 1kg mass is placed on top of the brick. What force will be required to start it sliding?
Answers
Answered by
JAC OB254
F=ma
a=F/m
a=8/2
a=4m/s^2
F=(2+1)4
F=12N
a=F/m
a=8/2
a=4m/s^2
F=(2+1)4
F=12N
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